Base | Representation |
---|---|
bin | 111001000000100011… |
… | …1110100100100100101 |
3 | 102201000000222110122011 |
4 | 1302001013310210211 |
5 | 4001211400123433 |
6 | 132124053034221 |
7 | 11562546456202 |
oct | 1620107644445 |
9 | 381000873564 |
10 | 122425395493 |
11 | 47a13a42705 |
12 | 1b888025971 |
13 | b71082522b |
14 | 5cd54d6ca9 |
15 | 32b7d963cd |
hex | 1c811f4925 |
122425395493 has 2 divisors, whose sum is σ = 122425395494. Its totient is φ = 122425395492.
The previous prime is 122425395461. The next prime is 122425395497. The reversal of 122425395493 is 394593524221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101214968449 + 21210427044 = 318143^2 + 145638^2 .
It is a cyclic number.
It is not a de Polignac number, because 122425395493 - 25 = 122425395461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122425395497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61212697746 + 61212697747.
It is an arithmetic number, because the mean of its divisors is an integer number (61212697747).
Almost surely, 2122425395493 is an apocalyptic number.
It is an amenable number.
122425395493 is a deficient number, since it is larger than the sum of its proper divisors (1).
122425395493 is an equidigital number, since it uses as much as digits as its factorization.
122425395493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2332800, while the sum is 49.
The spelling of 122425395493 in words is "one hundred twenty-two billion, four hundred twenty-five million, three hundred ninety-five thousand, four hundred ninety-three".
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