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122439250993 is a prime number
BaseRepresentation
bin111001000000111110…
…0101011010000110001
3102201001000001101210211
41302001330223100301
54001223422012433
6132125310024121
711563105314223
oct1620174532061
9381030041724
10122439250993
1147a20846534
121b8907a8041
13b713666957
145cd72a2413
1532b91d18cd
hex1c81f2b431

122439250993 has 2 divisors, whose sum is σ = 122439250994. Its totient is φ = 122439250992.

The previous prime is 122439250981. The next prime is 122439251021. The reversal of 122439250993 is 399052934221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88975134369 + 33464116624 = 298287^2 + 182932^2 .

It is a cyclic number.

It is not a de Polignac number, because 122439250993 - 25 = 122439250961 is a prime.

It is not a weakly prime, because it can be changed into another prime (122439250793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61219625496 + 61219625497.

It is an arithmetic number, because the mean of its divisors is an integer number (61219625497).

Almost surely, 2122439250993 is an apocalyptic number.

It is an amenable number.

122439250993 is a deficient number, since it is larger than the sum of its proper divisors (1).

122439250993 is an equidigital number, since it uses as much as digits as its factorization.

122439250993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1049760, while the sum is 49.

The spelling of 122439250993 in words is "one hundred twenty-two billion, four hundred thirty-nine million, two hundred fifty thousand, nine hundred ninety-three".