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12244251132959 is a prime number
BaseRepresentation
bin1011001000101101011000…
…1111010100010000011111
31121100112112220200020220012
42302023112033110100133
53101102211242223314
642012533055313435
72402421646254656
oct262132617242037
947315486606805
1012244251132959
1139a083761516a
121459026b1b87b
136aa821730cb1
143048a6ab419d
1516377b1ab93e
hexb22d63d441f

12244251132959 has 2 divisors, whose sum is σ = 12244251132960. Its totient is φ = 12244251132958.

The previous prime is 12244251132947. The next prime is 12244251133069. The reversal of 12244251132959 is 95923115244221.

12244251132959 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (95923115244221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12244251132959 - 28 = 12244251132703 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12244251132929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6122125566479 + 6122125566480.

It is an arithmetic number, because the mean of its divisors is an integer number (6122125566480).

Almost surely, 212244251132959 is an apocalyptic number.

12244251132959 is a deficient number, since it is larger than the sum of its proper divisors (1).

12244251132959 is an equidigital number, since it uses as much as digits as its factorization.

12244251132959 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1555200, while the sum is 50.

The spelling of 12244251132959 in words is "twelve trillion, two hundred forty-four billion, two hundred fifty-one million, one hundred thirty-two thousand, nine hundred fifty-nine".