12244312433 has 4 divisors (see below), whose sum is σ = 12262240368. Its totient is φ = 12226384500.

The previous prime is 12244312429. The next prime is 12244312477. The reversal of 12244312433 is 33421344221.

12244312433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12244312433 - 2² = 12244312429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12244312396 and 12244312405.

It is not an unprimeable number, because it can be changed into a prime (12244312733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8962943 + ... + 8964308.

It is an arithmetic number, because the mean of its divisors is an integer number (3065560092).

Almost surely, 2^12244312433 is an apocalyptic number.

It is an amenable number.

12244312433 is a deficient number, since it is larger than the sum of its proper divisors (17927935).

12244312433 is an equidigital number, since it uses as much as digits as its factorization.

12244312433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17927934.

The product of its digits is 13824, while the sum is 29.

Adding to 12244312433 its reverse (33421344221), we get a palindrome (45665656654).

The spelling of 12244312433 in words is "twelve billion, two hundred forty-four million, three hundred twelve thousand, four hundred thirty-three".