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12248444004161 is a prime number
BaseRepresentation
bin1011001000111101000000…
…1001110110011101000001
31121100221101010022011220012
42302033100021312131001
53101134303131113121
642014505115154305
72402630601135161
oct262172011663501
947327333264805
1012248444004161
1139a2599362382
1214599b7145995
136ab03c2b1c81
14304b838b25a1
1516392432dc5b
hexb23d0276741

12248444004161 has 2 divisors, whose sum is σ = 12248444004162. Its totient is φ = 12248444004160.

The previous prime is 12248444004151. The next prime is 12248444004163. The reversal of 12248444004161 is 16140044484221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11925315423025 + 323128581136 = 3453305^2 + 568444^2 .

It is a cyclic number.

It is not a de Polignac number, because 12248444004161 - 210 = 12248444003137 is a prime.

Together with 12248444004163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12248444004163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6124222002080 + 6124222002081.

It is an arithmetic number, because the mean of its divisors is an integer number (6124222002081).

Almost surely, 212248444004161 is an apocalyptic number.

It is an amenable number.

12248444004161 is a deficient number, since it is larger than the sum of its proper divisors (1).

12248444004161 is an equidigital number, since it uses as much as digits as its factorization.

12248444004161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 196608, while the sum is 41.

Adding to 12248444004161 its reverse (16140044484221), we get a palindrome (28388488488382).

The spelling of 12248444004161 in words is "twelve trillion, two hundred forty-eight billion, four hundred forty-four million, four thousand, one hundred sixty-one".