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1225035413153 = 9901123728453
BaseRepresentation
bin10001110100111001110…
…011001111011010100001
311100010000211020212111122
4101310321303033122201
5130032333031210103
62334435024222025
7154335343126526
oct21647163173241
94303024225448
101225035413153
11432597610592
12179505a6a915
138b69c270046
144341348d14d
1521ceca55b38
hex11d39ccf6a1

1225035413153 has 4 divisors (see below), whose sum is σ = 1225159151508. Its totient is φ = 1224911674800.

The previous prime is 1225035413149. The next prime is 1225035413191. The reversal of 1225035413153 is 3513145305221.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 851057910784 + 373977502369 = 922528^2 + 611537^2 .

It is a cyclic number.

It is not a de Polignac number, because 1225035413153 - 22 = 1225035413149 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1225035413123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61854326 + ... + 61874127.

It is an arithmetic number, because the mean of its divisors is an integer number (306289787877).

Almost surely, 21225035413153 is an apocalyptic number.

It is an amenable number.

1225035413153 is a deficient number, since it is larger than the sum of its proper divisors (123738355).

1225035413153 is an equidigital number, since it uses as much as digits as its factorization.

1225035413153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123738354.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 1225035413153 in words is "one trillion, two hundred twenty-five billion, thirty-five million, four hundred thirteen thousand, one hundred fifty-three".

Divisors: 1 9901 123728453 1225035413153