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12250723942033 is a prime number
BaseRepresentation
bin1011001001000101100000…
…0011000111111010010001
31121101011021000102000200121
42302101120003013322101
53101203440312121113
642015523242150241
72403041234241313
oct262213003077221
947334230360617
1012250723942033
1139a3559320455
12145a3327b2381
136ab313751635
14304d1c5db7b3
15163a0958ae8d
hexb24580c7e91

12250723942033 has 2 divisors, whose sum is σ = 12250723942034. Its totient is φ = 12250723942032.

The previous prime is 12250723942031. The next prime is 12250723942103. The reversal of 12250723942033 is 33024932705221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11494351070224 + 756372871809 = 3390332^2 + 869697^2 .

It is a cyclic number.

It is not a de Polignac number, because 12250723942033 - 21 = 12250723942031 is a prime.

Together with 12250723942031, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12250723942031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6125361971016 + 6125361971017.

It is an arithmetic number, because the mean of its divisors is an integer number (6125361971017).

Almost surely, 212250723942033 is an apocalyptic number.

It is an amenable number.

12250723942033 is a deficient number, since it is larger than the sum of its proper divisors (1).

12250723942033 is an equidigital number, since it uses as much as digits as its factorization.

12250723942033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 43.

The spelling of 12250723942033 in words is "twelve trillion, two hundred fifty billion, seven hundred twenty-three million, nine hundred forty-two thousand, thirty-three".