Base | Representation |
---|---|
bin | 1011001001000110111111… |
… | …0110100101110111011111 |
3 | 1121101012021211220000121112 |
4 | 2302101233312211313133 |
5 | 3101210300031410142 |
6 | 42020031030052235 |
7 | 2403054153641456 |
oct | 262215766456737 |
9 | 47335254800545 |
10 | 12251123310047 |
11 | 39a37437a4566 |
12 | 145a4244aa07b |
13 | 6ab37840137b |
14 | 304d59679b9d |
15 | 163a2e677382 |
hex | b246fda5ddf |
12251123310047 has 2 divisors, whose sum is σ = 12251123310048. Its totient is φ = 12251123310046.
The previous prime is 12251123309927. The next prime is 12251123310071. The reversal of 12251123310047 is 74001332115221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12251123310047 - 218 = 12251123047903 is a prime.
It is a super-2 number, since 2×122511233100472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12251123309995 and 12251123310022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12251123310847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6125561655023 + 6125561655024.
It is an arithmetic number, because the mean of its divisors is an integer number (6125561655024).
Almost surely, 212251123310047 is an apocalyptic number.
12251123310047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12251123310047 is an equidigital number, since it uses as much as digits as its factorization.
12251123310047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 12251123310047 its reverse (74001332115221), we get a palindrome (86252455425268).
The spelling of 12251123310047 in words is "twelve trillion, two hundred fifty-one billion, one hundred twenty-three million, three hundred ten thousand, forty-seven".
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