122535401404031 has 32 divisors (see below), whose sum is σ = 157704339947520. Its totient is φ = 92399237762400.

The previous prime is 122535401404027. The next prime is 122535401404111. The reversal of 122535401404031 is 130404104535221.

It is a cyclic number.

It is not a de Polignac number, because 122535401404031 - 2² = 122535401404027 is a prime.

It is a super-2 number, since 2×122535401404031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122535401403982 and 122535401404000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122535401404021) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79022390 + ... + 80558108.

It is an arithmetic number, because the mean of its divisors is an integer number (4928260623360).

Almost surely, 2^{122535401404031} is an apocalyptic number.

122535401404031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

122535401404031 is a deficient number, since it is larger than the sum of its proper divisors (35168938543489).

122535401404031 is a wasteful number, since it uses less digits than its factorization.

122535401404031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1569195.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 122535401404031 its reverse (130404104535221), we get a palindrome (252939505939252).

The spelling of 122535401404031 in words is "one hundred twenty-two trillion, five hundred thirty-five billion, four hundred one million, four hundred four thousand, thirty-one".