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1225520414311 = 3784732380913
BaseRepresentation
bin10001110101010110101…
…101010111111001100111
311100011021121212111000111
4101311112231113321213
5130034331211224221
62334555111353451
7154353352434214
oct21652655277147
94304247774014
101225520414311
11432816363096
12179620382887
138b7488a318b
144345ba5cb0b
1521d2a409be1
hex11d56b57e67

1225520414311 has 4 divisors (see below), whose sum is σ = 1225552833072. Its totient is φ = 1225487995552.

The previous prime is 1225520414291. The next prime is 1225520414353. The reversal of 1225520414311 is 1134140255221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1225520414311 - 213 = 1225520406119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1225520415311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16152610 + ... + 16228303.

It is an arithmetic number, because the mean of its divisors is an integer number (306388208268).

Almost surely, 21225520414311 is an apocalyptic number.

1225520414311 is a deficient number, since it is larger than the sum of its proper divisors (32418761).

1225520414311 is an equidigital number, since it uses as much as digits as its factorization.

1225520414311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32418760.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 1225520414311 its reverse (1134140255221), we get a palindrome (2359660669532).

The spelling of 1225520414311 in words is "one trillion, two hundred twenty-five billion, five hundred twenty million, four hundred fourteen thousand, three hundred eleven".

Divisors: 1 37847 32380913 1225520414311