Base | Representation |
---|---|
bin | 10001110101010110101… |
… | …101010111111001100111 |
3 | 11100011021121212111000111 |
4 | 101311112231113321213 |
5 | 130034331211224221 |
6 | 2334555111353451 |
7 | 154353352434214 |
oct | 21652655277147 |
9 | 4304247774014 |
10 | 1225520414311 |
11 | 432816363096 |
12 | 179620382887 |
13 | 8b7488a318b |
14 | 4345ba5cb0b |
15 | 21d2a409be1 |
hex | 11d56b57e67 |
1225520414311 has 4 divisors (see below), whose sum is σ = 1225552833072. Its totient is φ = 1225487995552.
The previous prime is 1225520414291. The next prime is 1225520414353. The reversal of 1225520414311 is 1134140255221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1225520414311 - 213 = 1225520406119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1225520415311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16152610 + ... + 16228303.
It is an arithmetic number, because the mean of its divisors is an integer number (306388208268).
Almost surely, 21225520414311 is an apocalyptic number.
1225520414311 is a deficient number, since it is larger than the sum of its proper divisors (32418761).
1225520414311 is an equidigital number, since it uses as much as digits as its factorization.
1225520414311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32418760.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1225520414311 its reverse (1134140255221), we get a palindrome (2359660669532).
The spelling of 1225520414311 in words is "one trillion, two hundred twenty-five billion, five hundred twenty million, four hundred fourteen thousand, three hundred eleven".
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