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12255423322117 is a prime number
BaseRepresentation
bin1011001001010111000000…
…1001110101100000000101
31121101121101112010021020211
42302111300021311200011
53101243101332301432
642022021434155421
72403265546305013
oct262256011654005
947347345107224
1012255423322117
1139a554aa70248
12145b224582b71
136ab8b2226201
143052467a78b3
15163bd1e0ed47
hexb2570275805

12255423322117 has 2 divisors, whose sum is σ = 12255423322118. Its totient is φ = 12255423322116.

The previous prime is 12255423322031. The next prime is 12255423322159. The reversal of 12255423322117 is 71122332455221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7345693566436 + 4909729755681 = 2710294^2 + 2215791^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12255423322117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12255423322117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12255423322517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6127711661058 + 6127711661059.

It is an arithmetic number, because the mean of its divisors is an integer number (6127711661059).

Almost surely, 212255423322117 is an apocalyptic number.

It is an amenable number.

12255423322117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12255423322117 is an equidigital number, since it uses as much as digits as its factorization.

12255423322117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 201600, while the sum is 40.

Adding to 12255423322117 its reverse (71122332455221), we get a palindrome (83377755777338).

The spelling of 12255423322117 in words is "twelve trillion, two hundred fifty-five billion, four hundred twenty-three million, three hundred twenty-two thousand, one hundred seventeen".