Base | Representation |
---|---|
bin | 11011110111011001100110… |
… | …001011000100111111101110 |
3 | 121001221002002122120110200222 |
4 | 123313121212023010333232 |
5 | 112030412212104113032 |
6 | 1112352401230251342 |
7 | 34546154034401543 |
oct | 3367314613047756 |
9 | 531832078513628 |
10 | 122554311004142 |
11 | 3605aa9a639786 |
12 | 118b3a1a956b52 |
13 | 534ca8ba51944 |
14 | 2239935c22bca |
15 | e27dbb315a12 |
hex | 6f76662c4fee |
122554311004142 has 4 divisors (see below), whose sum is σ = 183831466506216. Its totient is φ = 61277155502070.
The previous prime is 122554311004127. The next prime is 122554311004201. The reversal of 122554311004142 is 241400113455221.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30638577751034 + ... + 30638577751037.
It is an arithmetic number, because the mean of its divisors is an integer number (45957866626554).
Almost surely, 2122554311004142 is an apocalyptic number.
122554311004142 is a deficient number, since it is larger than the sum of its proper divisors (61277155502074).
122554311004142 is an equidigital number, since it uses as much as digits as its factorization.
122554311004142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61277155502073.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 122554311004142 its reverse (241400113455221), we get a palindrome (363954424459363).
The spelling of 122554311004142 in words is "one hundred twenty-two trillion, five hundred fifty-four billion, three hundred eleven million, four thousand, one hundred forty-two".
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