Base | Representation |
---|---|
bin | 11011110111011010011100… |
… | …111100110010000000001110 |
3 | 121001221011110200211110102122 |
4 | 123313122130330302000032 |
5 | 112030421102340100324 |
6 | 1112353032335452542 |
7 | 34546215563640251 |
oct | 3367323474620016 |
9 | 531834420743378 |
10 | 122555230003214 |
11 | 36060421368348 |
12 | 118b4036687152 |
13 | 534cba726ac88 |
14 | 22399c1cc7098 |
15 | e27e21d46a5e |
hex | 6f769cf3200e |
122555230003214 has 4 divisors (see below), whose sum is σ = 183832845004824. Its totient is φ = 61277615001606.
The previous prime is 122555230003211. The next prime is 122555230003231. The reversal of 122555230003214 is 412300032555221.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1225552300032142 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122555230003211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30638807500802 + ... + 30638807500805.
It is an arithmetic number, because the mean of its divisors is an integer number (45958211251206).
Almost surely, 2122555230003214 is an apocalyptic number.
122555230003214 is a deficient number, since it is larger than the sum of its proper divisors (61277615001610).
122555230003214 is an equidigital number, since it uses as much as digits as its factorization.
122555230003214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61277615001609.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 122555230003214 its reverse (412300032555221), we get a palindrome (534855262558435).
The spelling of 122555230003214 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, two hundred thirty million, three thousand, two hundred fourteen".
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