Base | Representation |
---|---|
bin | 11011110111011010100001… |
… | …010011101011000101011111 |
3 | 121001221011122210101211021112 |
4 | 123313122201103223011133 |
5 | 112030421230044104210 |
6 | 1112353043510452235 |
7 | 34546220442235421 |
oct | 3367324123530537 |
9 | 531834583354245 |
10 | 122555303113055 |
11 | 360604596628aa |
12 | 118b405706407b |
13 | 534cbb9458137 |
14 | 22399cb8b8811 |
15 | e27e28488d05 |
hex | 6f76a14eb15f |
122555303113055 has 16 divisors (see below), whose sum is σ = 147554011874304. Its totient is φ = 97719388277280.
The previous prime is 122555303113039. The next prime is 122555303113151. The reversal of 122555303113055 is 550311303555221.
It is not a de Polignac number, because 122555303113055 - 24 = 122555303113039 is a prime.
It is a super-2 number, since 2×1225553031130552 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11273207 + ... + 19292376.
It is an arithmetic number, because the mean of its divisors is an integer number (9222125742144).
Almost surely, 2122555303113055 is an apocalyptic number.
122555303113055 is a deficient number, since it is larger than the sum of its proper divisors (24998708761249).
122555303113055 is a wasteful number, since it uses less digits than its factorization.
122555303113055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30568246.
The product of its (nonzero) digits is 337500, while the sum is 41.
Adding to 122555303113055 its reverse (550311303555221), we get a palindrome (672866606668276).
The spelling of 122555303113055 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, three hundred three million, one hundred thirteen thousand, fifty-five".
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