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122555303113055 = 5347231130565583
BaseRepresentation
bin11011110111011010100001…
…010011101011000101011111
3121001221011122210101211021112
4123313122201103223011133
5112030421230044104210
61112353043510452235
734546220442235421
oct3367324123530537
9531834583354245
10122555303113055
11360604596628aa
12118b405706407b
13534cbb9458137
1422399cb8b8811
15e27e28488d05
hex6f76a14eb15f

122555303113055 has 16 divisors (see below), whose sum is σ = 147554011874304. Its totient is φ = 97719388277280.

The previous prime is 122555303113039. The next prime is 122555303113151. The reversal of 122555303113055 is 550311303555221.

It is not a de Polignac number, because 122555303113055 - 24 = 122555303113039 is a prime.

It is a super-2 number, since 2×1225553031130552 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11273207 + ... + 19292376.

It is an arithmetic number, because the mean of its divisors is an integer number (9222125742144).

Almost surely, 2122555303113055 is an apocalyptic number.

122555303113055 is a deficient number, since it is larger than the sum of its proper divisors (24998708761249).

122555303113055 is a wasteful number, since it uses less digits than its factorization.

122555303113055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30568246.

The product of its (nonzero) digits is 337500, while the sum is 41.

Adding to 122555303113055 its reverse (550311303555221), we get a palindrome (672866606668276).

The spelling of 122555303113055 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, three hundred three million, one hundred thirteen thousand, fifty-five".

Divisors: 1 5 347 1735 2311 11555 801917 4009585 30565583 152827915 10606257301 53031286505 70637062313 353185311565 24511060622611 122555303113055