Base | Representation |
---|---|
bin | 10001110101101010010… |
… | …111011100101010000111 |
3 | 11100012010121102212221212 |
4 | 101311222113130222013 |
5 | 130041020123222301 |
6 | 2335051532202035 |
7 | 154364465604362 |
oct | 21655227345207 |
9 | 4305117385855 |
10 | 1225850210951 |
11 | 4329755391a3 |
12 | 1796b290931b |
13 | 8b79c004512 |
14 | 4348d78b0d9 |
15 | 21d493524bb |
hex | 11d6a5dca87 |
1225850210951 has 2 divisors, whose sum is σ = 1225850210952. Its totient is φ = 1225850210950.
The previous prime is 1225850210933. The next prime is 1225850210987. The reversal of 1225850210951 is 1590120585221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1225850210951 - 226 = 1225783102087 is a prime.
It is a super-2 number, since 2×12258502109512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1225850210899 and 1225850210908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1225850218951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612925105475 + 612925105476.
It is an arithmetic number, because the mean of its divisors is an integer number (612925105476).
Almost surely, 21225850210951 is an apocalyptic number.
1225850210951 is a deficient number, since it is larger than the sum of its proper divisors (1).
1225850210951 is an equidigital number, since it uses as much as digits as its factorization.
1225850210951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 41.
The spelling of 1225850210951 in words is "one trillion, two hundred twenty-five billion, eight hundred fifty million, two hundred ten thousand, nine hundred fifty-one".
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