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1226140725497 is a prime number
BaseRepresentation
bin10001110101111011101…
…011101011000011111001
311100012212212002112222212
4101311323223223003321
5130042114011203442
62335140431024505
7154404624126512
oct21657353530371
94305785075885
101226140725497
11433004524066
1217977406b135
138b817260a0c
14434ba1b1a09
1521d64adaa82
hex11d7baeb0f9

1226140725497 has 2 divisors, whose sum is σ = 1226140725498. Its totient is φ = 1226140725496.

The previous prime is 1226140725479. The next prime is 1226140725547. The reversal of 1226140725497 is 7945270416221.

Together with previous prime (1226140725479) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (1226140725547) can be obtained adding 1226140725497 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 970108773481 + 256031952016 = 984941^2 + 505996^2 .

It is a cyclic number.

It is not a de Polignac number, because 1226140725497 - 214 = 1226140709113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1226140725197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 613070362748 + 613070362749.

It is an arithmetic number, because the mean of its divisors is an integer number (613070362749).

Almost surely, 21226140725497 is an apocalyptic number.

It is an amenable number.

1226140725497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1226140725497 is an equidigital number, since it uses as much as digits as its factorization.

1226140725497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1693440, while the sum is 50.

The spelling of 1226140725497 in words is "one trillion, two hundred twenty-six billion, one hundred forty million, seven hundred twenty-five thousand, four hundred ninety-seven".