Base | Representation |
---|---|
bin | 10110110101111000… |
… | …00100100110000101 |
3 | 1011122122012210110200 |
4 | 23122330010212011 |
5 | 200103324141031 |
6 | 5344505041113 |
7 | 612614521164 |
oct | 133274044605 |
9 | 34578183420 |
10 | 12263115141 |
11 | 5223232a02 |
12 | 2462a86199 |
13 | 1205819964 |
14 | 84494d3db |
15 | 4bb8e58e6 |
hex | 2daf04985 |
12263115141 has 6 divisors (see below), whose sum is σ = 17713388550. Its totient is φ = 8175410088.
The previous prime is 12263115113. The next prime is 12263115149. The reversal of 12263115141 is 14151136221.
12263115141 is a `hidden beast` number, since 1 + 2 + 2 + 631 + 15 + 14 + 1 = 666.
It can be written as a sum of positive squares in only one way, i.e., 12131921025 + 131194116 = 110145^2 + 11454^2 .
It is not a de Polignac number, because 12263115141 - 210 = 12263114117 is a prime.
It is a super-2 number, since 2×122631151412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12263115149) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 681284166 + ... + 681284183.
It is an arithmetic number, because the mean of its divisors is an integer number (2952231425).
Almost surely, 212263115141 is an apocalyptic number.
It is an amenable number.
12263115141 is a deficient number, since it is larger than the sum of its proper divisors (5450273409).
12263115141 is a wasteful number, since it uses less digits than its factorization.
12263115141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1362568355 (or 1362568352 counting only the distinct ones).
The product of its digits is 1440, while the sum is 27.
The spelling of 12263115141 in words is "twelve billion, two hundred sixty-three million, one hundred fifteen thousand, one hundred forty-one".
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