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12266753657 is a prime number
BaseRepresentation
bin10110110110010011…
…11100111001111001
31011122220001122120112
423123021330321321
5200110242104112
65345115034105
7612660454124
oct133311747171
934586048515
1012266753657
115225298644
12246413b935
1312064c1b22
148452193bb
154bbdb3a22
hex2db27ce79

12266753657 has 2 divisors, whose sum is σ = 12266753658. Its totient is φ = 12266753656.

The previous prime is 12266753623. The next prime is 12266753659. The reversal of 12266753657 is 75635766221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11495913961 + 770839696 = 107219^2 + 27764^2 .

It is an emirp because it is prime and its reverse (75635766221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12266753657 - 218 = 12266491513 is a prime.

It is a super-3 number, since 3×122667536573 (a number of 31 digits) contains 333 as substring.

Together with 12266753659, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12266753659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6133376828 + 6133376829.

It is an arithmetic number, because the mean of its divisors is an integer number (6133376829).

Almost surely, 212266753657 is an apocalyptic number.

It is an amenable number.

12266753657 is a deficient number, since it is larger than the sum of its proper divisors (1).

12266753657 is an equidigital number, since it uses as much as digits as its factorization.

12266753657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3175200, while the sum is 50.

The spelling of 12266753657 in words is "twelve billion, two hundred sixty-six million, seven hundred fifty-three thousand, six hundred fifty-seven".