122925404373 has 4 divisors (see below), whose sum is σ = 163900539168. Its totient is φ = 81950269580.

The previous prime is 122925404369. The next prime is 122925404387. The reversal of 122925404373 is 373404529221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 122925404373 - 2² = 122925404369 is a prime.

It is a super-2 number, since 2×122925404373² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122925400373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20487567393 + ... + 20487567398.

It is an arithmetic number, because the mean of its divisors is an integer number (40975134792).

Almost surely, 2^122925404373 is an apocalyptic number.

It is an amenable number.

122925404373 is a deficient number, since it is larger than the sum of its proper divisors (40975134795).

122925404373 is an equidigital number, since it uses as much as digits as its factorization.

122925404373 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40975134794.

The product of its (nonzero) digits is 362880, while the sum is 42.

The spelling of 122925404373 in words is "one hundred twenty-two billion, nine hundred twenty-five million, four hundred four thousand, three hundred seventy-three".