Search a number
-
+
1229437481 is a prime number
BaseRepresentation
bin100100101000111…
…1011101000101001
310011200101220011112
41021101323220221
510004213444411
6321555040105
742316021556
oct11121735051
93150356145
101229437481
11580a92638
122a38a0035
131679303cc
14b93d3a2d
1572e02b8b
hex4947ba29

1229437481 has 2 divisors, whose sum is σ = 1229437482. Its totient is φ = 1229437480.

The previous prime is 1229437477. The next prime is 1229437483. The reversal of 1229437481 is 1847349221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 790115881 + 439321600 = 28109^2 + 20960^2 .

It is an emirp because it is prime and its reverse (1847349221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1229437481 - 22 = 1229437477 is a prime.

It is a super-2 number, since 2×12294374812 = 3023033039375250722, which contains 22 as substring.

Together with 1229437483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1229437483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 614718740 + 614718741.

It is an arithmetic number, because the mean of its divisors is an integer number (614718741).

Almost surely, 21229437481 is an apocalyptic number.

It is an amenable number.

1229437481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1229437481 is an equidigital number, since it uses as much as digits as its factorization.

1229437481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96768, while the sum is 41.

The square root of 1229437481 is about 35063.3352806033. The cubic root of 1229437481 is about 1071.2779098062.

The spelling of 1229437481 in words is "one billion, two hundred twenty-nine million, four hundred thirty-seven thousand, four hundred eighty-one".