Base | Representation |
---|---|
bin | 1011001011110110000011… |
… | …1011111110011101101101 |
3 | 1121112200120222010120012121 |
4 | 2302331200323332131231 |
5 | 3102443021113003113 |
6 | 42053402143032541 |
7 | 2406336551461144 |
oct | 262754073763555 |
9 | 47480528116177 |
10 | 12298117703533 |
11 | 3a11669917992 |
12 | 146755a89b751 |
13 | 6b29275759ac |
14 | 307336b4475b |
15 | 164d8021be8d |
hex | b2f60efe76d |
12298117703533 has 2 divisors, whose sum is σ = 12298117703534. Its totient is φ = 12298117703532.
The previous prime is 12298117703411. The next prime is 12298117703551. The reversal of 12298117703533 is 33530771189221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11558082479524 + 740035224009 = 3399718^2 + 860253^2 .
It is a cyclic number.
It is not a de Polignac number, because 12298117703533 - 213 = 12298117695341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12298117706533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6149058851766 + 6149058851767.
It is an arithmetic number, because the mean of its divisors is an integer number (6149058851767).
Almost surely, 212298117703533 is an apocalyptic number.
It is an amenable number.
12298117703533 is a deficient number, since it is larger than the sum of its proper divisors (1).
12298117703533 is an equidigital number, since it uses as much as digits as its factorization.
12298117703533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1905120, while the sum is 52.
The spelling of 12298117703533 in words is "twelve trillion, two hundred ninety-eight billion, one hundred seventeen million, seven hundred three thousand, five hundred thirty-three".
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