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123000031323133 is a prime number
BaseRepresentation
bin11011111101111000101101…
…001011001010001111111101
3121010111200120122222200122121
4123331320231023022033331
5112110213031004320013
61113333233451442541
734623313303530316
oct3375705513121775
9533450518880577
10123000031323133
1136212025094478
1211966291756451
135382b125a5b73
14225333a19b60d
15e347a69d558d
hex6fde2d2ca3fd

123000031323133 has 2 divisors, whose sum is σ = 123000031323134. Its totient is φ = 123000031323132.

The previous prime is 123000031323061. The next prime is 123000031323157. The reversal of 123000031323133 is 331323130000321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120549046947289 + 2450984375844 = 10979483^2 + 1565562^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123000031323133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123000031323098 and 123000031323107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123000031323233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61500015661566 + 61500015661567.

It is an arithmetic number, because the mean of its divisors is an integer number (61500015661567).

Almost surely, 2123000031323133 is an apocalyptic number.

It is an amenable number.

123000031323133 is a deficient number, since it is larger than the sum of its proper divisors (1).

123000031323133 is an equidigital number, since it uses as much as digits as its factorization.

123000031323133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 123000031323133 its reverse (331323130000321), we get a palindrome (454323161323454).

The spelling of 123000031323133 in words is "one hundred twenty-three trillion, thirty-one million, three hundred twenty-three thousand, one hundred thirty-three".