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123000311550433 is a prime number
BaseRepresentation
bin11011111101111000111101…
…111000001001000111100001
3121010111201022012021201020111
4123331320331320021013201
5112110214114224103213
61113333321342011321
734623323245445452
oct3375707570110741
9533451265251214
10123000311550433
1136212159293389
121196634b576b41
135382b5866cb35
1422533654a5129
15e347c13daa3d
hex6fde3de091e1

123000311550433 has 2 divisors, whose sum is σ = 123000311550434. Its totient is φ = 123000311550432.

The previous prime is 123000311550377. The next prime is 123000311550481. The reversal of 123000311550433 is 334055113000321.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64457261846784 + 58543049703649 = 8028528^2 + 7651343^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123000311550433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123000311550395 and 123000311550404.

It is not a weakly prime, because it can be changed into another prime (123000311553433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61500155775216 + 61500155775217.

It is an arithmetic number, because the mean of its divisors is an integer number (61500155775217).

Almost surely, 2123000311550433 is an apocalyptic number.

It is an amenable number.

123000311550433 is a deficient number, since it is larger than the sum of its proper divisors (1).

123000311550433 is an equidigital number, since it uses as much as digits as its factorization.

123000311550433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 123000311550433 its reverse (334055113000321), we get a palindrome (457055424550754).

The spelling of 123000311550433 in words is "one hundred twenty-three trillion, three hundred eleven million, five hundred fifty thousand, four hundred thirty-three".