Search a number
-
+
123000340533134 = 261500170266567
BaseRepresentation
bin11011111101111000111111…
…100110101100111110001110
3121010111201101012211012000212
4123331320333212230332032
5112110214144134030014
61113333324255122422
734623324050006231
oct3375707746547616
9533451335735025
10123000340533134
1136212173689529
1211966359213412
135382b61679a6c
14225336928b418
15e347c3c1323e
hex6fde3f9acf8e

123000340533134 has 4 divisors (see below), whose sum is σ = 184500510799704. Its totient is φ = 61500170266566.

The previous prime is 123000340533053. The next prime is 123000340533149. The reversal of 123000340533134 is 431335043000321.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 123000340533134.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30750085133282 + ... + 30750085133285.

It is an arithmetic number, because the mean of its divisors is an integer number (46125127699926).

Almost surely, 2123000340533134 is an apocalyptic number.

123000340533134 is a deficient number, since it is larger than the sum of its proper divisors (61500170266570).

123000340533134 is an equidigital number, since it uses as much as digits as its factorization.

123000340533134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61500170266569.

The product of its (nonzero) digits is 38880, while the sum is 32.

Adding to 123000340533134 its reverse (431335043000321), we get a palindrome (554335383533455).

The spelling of 123000340533134 in words is "one hundred twenty-three trillion, three hundred forty million, five hundred thirty-three thousand, one hundred thirty-four".

Divisors: 1 2 61500170266567 123000340533134