Base | Representation |
---|---|
bin | 1011001011111101011111… |
… | …0111111001001110101110 |
3 | 1121112212202000212100001111 |
4 | 2302333113313321032232 |
5 | 3103011112424402342 |
6 | 42054332143502234 |
7 | 2406440161322302 |
oct | 262772767711656 |
9 | 47485660770044 |
10 | 12300113122222 |
11 | 3a124a3215542 |
12 | 1467a16bb797a |
13 | 6b2b84aa7a03 |
14 | 307485b69d02 |
15 | 164e4a4c7217 |
hex | b2fd7df93ae |
12300113122222 has 4 divisors (see below), whose sum is σ = 18450169683336. Its totient is φ = 6150056561110.
The previous prime is 12300113122123. The next prime is 12300113122273. The reversal of 12300113122222 is 22222131100321.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×123001131222222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12300113122193 and 12300113122202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3075028280554 + ... + 3075028280557.
It is an arithmetic number, because the mean of its divisors is an integer number (4612542420834).
Almost surely, 212300113122222 is an apocalyptic number.
12300113122222 is a deficient number, since it is larger than the sum of its proper divisors (6150056561114).
12300113122222 is an equidigital number, since it uses as much as digits as its factorization.
12300113122222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6150056561113.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 12300113122222 its reverse (22222131100321), we get a palindrome (34522244222543).
The spelling of 12300113122222 in words is "twelve trillion, three hundred billion, one hundred thirteen million, one hundred twenty-two thousand, two hundred twenty-two".
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