Base | Representation |
---|---|
bin | 10001111001100010011… |
… | …011110010111011100001 |
3 | 11100120212122202202212121 |
4 | 101321202123302323201 |
5 | 130123031044202241 |
6 | 2341020524024241 |
7 | 154602563226544 |
oct | 21714233627341 |
9 | 4316778682777 |
10 | 1230012100321 |
11 | 434710845294 |
12 | 17a474692081 |
13 | 8bcb3328654 |
14 | 4376640285b |
15 | 21ede904ad1 |
hex | 11e626f2ee1 |
1230012100321 has 2 divisors, whose sum is σ = 1230012100322. Its totient is φ = 1230012100320.
The previous prime is 1230012100279. The next prime is 1230012100399.
1230012100321 is nontrivially palindromic in base 10.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1185518104225 + 44493996096 = 1088815^2 + 210936^2 .
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1230012100321 - 213 = 1230012092129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1230012100295 and 1230012100304.
It is not a weakly prime, because it can be changed into another prime (1230012100621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615006050160 + 615006050161.
It is an arithmetic number, because the mean of its divisors is an integer number (615006050161).
Almost surely, 21230012100321 is an apocalyptic number.
It is an amenable number.
1230012100321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230012100321 is an equidigital number, since it uses as much as digits as its factorization.
1230012100321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
The spelling of 1230012100321 in words is "one trillion, two hundred thirty billion, twelve million, one hundred thousand, three hundred twenty-one".
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