Base | Representation |
---|---|
bin | 1011001011111101100011… |
… | …1100100011011111001111 |
3 | 1121112212210021201202212201 |
4 | 2302333120330203133033 |
5 | 3103011132031333403 |
6 | 42054334025342331 |
7 | 2406440500315210 |
oct | 262773074433717 |
9 | 47485707652781 |
10 | 12300131121103 |
11 | 3a12502399351 |
12 | 1467a210379a7 |
13 | 6b2b8873a337 |
14 | 3074882d3407 |
15 | 164e4bd8021d |
hex | b2fd8f237cf |
12300131121103 has 4 divisors (see below), whose sum is σ = 14057292709840. Its totient is φ = 10542969532368.
The previous prime is 12300131121037. The next prime is 12300131121119. The reversal of 12300131121103 is 30112113100321.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-12300131121103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12300131125103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 878580794358 + ... + 878580794371.
It is an arithmetic number, because the mean of its divisors is an integer number (3514323177460).
Almost surely, 212300131121103 is an apocalyptic number.
12300131121103 is a deficient number, since it is larger than the sum of its proper divisors (1757161588737).
12300131121103 is an equidigital number, since it uses as much as digits as its factorization.
12300131121103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1757161588736.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 12300131121103 its reverse (30112113100321), we get a palindrome (42412244221424).
The spelling of 12300131121103 in words is "twelve trillion, three hundred billion, one hundred thirty-one million, one hundred twenty-one thousand, one hundred three".
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