123001333315142 has 4 divisors (see below), whose sum is σ = 184501999972716. Its totient is φ = 61500666657570.

The previous prime is 123001333315139. The next prime is 123001333315313. The reversal of 123001333315142 is 241513333100321.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×123001333315142² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123001333315099 and 123001333315108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30750333328784 + ... + 30750333328787.

It is an arithmetic number, because the mean of its divisors is an integer number (46125499993179).

Almost surely, 2^{123001333315142} is an apocalyptic number.

123001333315142 is a deficient number, since it is larger than the sum of its proper divisors (61500666657574).

123001333315142 is an equidigital number, since it uses as much as digits as its factorization.

123001333315142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61500666657573.

The product of its (nonzero) digits is 19440, while the sum is 32.

Adding to 123001333315142 its reverse (241513333100321), we get a palindrome (364514666415463).

The spelling of 123001333315142 in words is "one hundred twenty-three trillion, one billion, three hundred thirty-three million, three hundred fifteen thousand, one hundred forty-two".