Base | Representation |
---|---|
bin | 1011001011111110010001… |
… | …1001011001011001001111 |
3 | 1121112220021200012222112121 |
4 | 2302333210121121121033 |
5 | 3103012030221400221 |
6 | 42054405051113411 |
7 | 2406445322242243 |
oct | 262774431313117 |
9 | 47486250188477 |
10 | 12300323231311 |
11 | 3a125a0882615 |
12 | 1467a75442867 |
13 | 6b2bb949140b |
14 | 3074a5a20423 |
15 | 164e5db7ba41 |
hex | b2fe465964f |
12300323231311 has 4 divisors (see below), whose sum is σ = 12303105484824. Its totient is φ = 12297540977800.
The previous prime is 12300323231269. The next prime is 12300323231323. The reversal of 12300323231311 is 11313232300321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12300323231311 - 29 = 12300323230799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12300323235311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1391120125 + ... + 1391128966.
It is an arithmetic number, because the mean of its divisors is an integer number (3075776371206).
Almost surely, 212300323231311 is an apocalyptic number.
12300323231311 is a deficient number, since it is larger than the sum of its proper divisors (2782253513).
12300323231311 is an equidigital number, since it uses as much as digits as its factorization.
12300323231311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2782253512.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 12300323231311 its reverse (11313232300321), we get a palindrome (23613555531632).
The spelling of 12300323231311 in words is "twelve trillion, three hundred billion, three hundred twenty-three million, two hundred thirty-one thousand, three hundred eleven".
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