12300400401 has 4 divisors (see below), whose sum is σ = 16400533872. Its totient is φ = 8200266932.

The previous prime is 12300400397. The next prime is 12300400403. The reversal of 12300400401 is 10400400321.

12300400401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12300400401 - 2² = 12300400397 is a prime.

It is a super-3 number, since 3×12300400401³ (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (12300400403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050066731 + ... + 2050066736.

It is an arithmetic number, because the mean of its divisors is an integer number (4100133468).

Almost surely, 2^12300400401 is an apocalyptic number.

It is an amenable number.

12300400401 is a deficient number, since it is larger than the sum of its proper divisors (4100133471).

12300400401 is an equidigital number, since it uses as much as digits as its factorization.

12300400401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4100133470.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12300400401 its reverse (10400400321), we get a palindrome (22700800722).

The spelling of 12300400401 in words is "twelve billion, three hundred million, four hundred thousand, four hundred one".