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12300404113 = 20396032567
BaseRepresentation
bin10110111010010100…
…10100010110010001
31011202020101021022201
423131022110112101
5200142400412423
65352320203201
7613546465324
oct133512242621
934666337281
1012300404113
115242291738
122473469501
13121047453a
148498987bb
154bed0e2ad
hex2dd294591

12300404113 has 4 divisors (see below), whose sum is σ = 12306438720. Its totient is φ = 12294369508.

The previous prime is 12300404101. The next prime is 12300404183. The reversal of 12300404113 is 31140400321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31140400321 = 167186469463.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12300404113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12300404183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3014245 + ... + 3018322.

It is an arithmetic number, because the mean of its divisors is an integer number (3076609680).

Almost surely, 212300404113 is an apocalyptic number.

It is an amenable number.

12300404113 is a deficient number, since it is larger than the sum of its proper divisors (6034607).

12300404113 is an equidigital number, since it uses as much as digits as its factorization.

12300404113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6034606.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 12300404113 its reverse (31140400321), we get a palindrome (43440804434).

The spelling of 12300404113 in words is "twelve billion, three hundred million, four hundred four thousand, one hundred thirteen".

Divisors: 1 2039 6032567 12300404113