Base | Representation |
---|---|
bin | 11011111110000010001011… |
… | …010010000010101010101001 |
3 | 121010112122211100101002111221 |
4 | 123332002023102002222221 |
5 | 112110344342212314402 |
6 | 1113342034504222041 |
7 | 34624123301060332 |
oct | 3376021322025251 |
9 | 533478740332457 |
10 | 123010200119977 |
11 | 3621637310a005 |
12 | 1196824b16a921 |
13 | 5383a73243b11 |
14 | 2253a228dd289 |
15 | e34b9e5d7337 |
hex | 6fe08b482aa9 |
123010200119977 has 2 divisors, whose sum is σ = 123010200119978. Its totient is φ = 123010200119976.
The previous prime is 123010200119923. The next prime is 123010200120007. The reversal of 123010200119977 is 779911002010321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 98081708911641 + 24928491208336 = 9903621^2 + 4992844^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123010200119977 is a prime.
It is not a weakly prime, because it can be changed into another prime (123010200119077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505100059988 + 61505100059989.
It is an arithmetic number, because the mean of its divisors is an integer number (61505100059989).
Almost surely, 2123010200119977 is an apocalyptic number.
It is an amenable number.
123010200119977 is a deficient number, since it is larger than the sum of its proper divisors (1).
123010200119977 is an equidigital number, since it uses as much as digits as its factorization.
123010200119977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47628, while the sum is 43.
The spelling of 123010200119977 in words is "one hundred twenty-three trillion, ten billion, two hundred million, one hundred nineteen thousand, nine hundred seventy-seven".
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