Base | Representation |
---|---|
bin | 11011111110000010001011… |
… | …010010000010101011000111 |
3 | 121010112122211100101002120001 |
4 | 123332002023102002223013 |
5 | 112110344342212320012 |
6 | 1113342034504222131 |
7 | 34624123301060404 |
oct | 3376021322025307 |
9 | 533478740332501 |
10 | 123010200120007 |
11 | 3621637310a032 |
12 | 1196824b16a947 |
13 | 5383a73243b35 |
14 | 2253a228dd2ab |
15 | e34b9e5d7357 |
hex | 6fe08b482ac7 |
123010200120007 has 2 divisors, whose sum is σ = 123010200120008. Its totient is φ = 123010200120006.
The previous prime is 123010200119977. The next prime is 123010200120023. The reversal of 123010200120007 is 700021002010321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123010200120007 - 219 = 123010199595719 is a prime.
It is a super-3 number, since 3×1230102001200073 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123010200120407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505100060003 + 61505100060004.
It is an arithmetic number, because the mean of its divisors is an integer number (61505100060004).
Almost surely, 2123010200120007 is an apocalyptic number.
123010200120007 is a deficient number, since it is larger than the sum of its proper divisors (1).
123010200120007 is an equidigital number, since it uses as much as digits as its factorization.
123010200120007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 19.
Adding to 123010200120007 its reverse (700021002010321), we get a palindrome (823031202130328).
The spelling of 123010200120007 in words is "one hundred twenty-three trillion, ten billion, two hundred million, one hundred twenty thousand, seven".
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