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123010211220037 is a prime number
BaseRepresentation
bin11011111110000010001011…
…111100011000101001000101
3121010112122212010021000221021
4123332002023330120221011
5112110344403033020122
61113342035542151141
734624123464321121
oct3376021374305105
9533478763230837
10123010211220037
1136216379400709
1211968252a224b1
135383a7562c2bb
142253a2418c581
15e34ba057b1c7
hex6fe08bf18a45

123010211220037 has 2 divisors, whose sum is σ = 123010211220038. Its totient is φ = 123010211220036.

The previous prime is 123010211219993. The next prime is 123010211220079. The reversal of 123010211220037 is 730022112010321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79851631328676 + 43158579891361 = 8935974^2 + 6569519^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123010211220037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123010211219993 and 123010211220020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123010211223037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505105610018 + 61505105610019.

It is an arithmetic number, because the mean of its divisors is an integer number (61505105610019).

Almost surely, 2123010211220037 is an apocalyptic number.

It is an amenable number.

123010211220037 is a deficient number, since it is larger than the sum of its proper divisors (1).

123010211220037 is an equidigital number, since it uses as much as digits as its factorization.

123010211220037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 123010211220037 its reverse (730022112010321), we get a palindrome (853032323230358).

The spelling of 123010211220037 in words is "one hundred twenty-three trillion, ten billion, two hundred eleven million, two hundred twenty thousand, thirty-seven".