Base | Representation |
---|---|
bin | 10110111010011001… |
… | …01101011011001101 |
3 | 1011202021120010102002 |
4 | 23131030231123031 |
5 | 200143030443432 |
6 | 5352341442045 |
7 | 613555016324 |
oct | 133514553315 |
9 | 34667503362 |
10 | 12301031117 |
11 | 524267a821 |
12 | 2473710325 |
13 | 1210633a4b |
14 | 8499bd0bb |
15 | 4bedd4e62 |
hex | 2dd32d6cd |
12301031117 has 2 divisors, whose sum is σ = 12301031118. Its totient is φ = 12301031116.
The previous prime is 12301031111. The next prime is 12301031203. The reversal of 12301031117 is 71113010321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11868141481 + 432889636 = 108941^2 + 20806^2 .
It is an emirp because it is prime and its reverse (71113010321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12301031117 - 218 = 12300768973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12301031111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150515558 + 6150515559.
It is an arithmetic number, because the mean of its divisors is an integer number (6150515559).
Almost surely, 212301031117 is an apocalyptic number.
It is an amenable number.
12301031117 is a deficient number, since it is larger than the sum of its proper divisors (1).
12301031117 is an equidigital number, since it uses as much as digits as its factorization.
12301031117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 12301031117 its reverse (71113010321), we get a palindrome (83414041438).
The spelling of 12301031117 in words is "twelve billion, three hundred one million, thirty-one thousand, one hundred seventeen".
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