Base | Representation |
---|---|
bin | 10001111001101000010… |
… | …001101111111111000001 |
3 | 11100121010111020012110122 |
4 | 101321220101233333001 |
5 | 130123231143130423 |
6 | 2341034345110025 |
7 | 154605163404644 |
oct | 21715021577701 |
9 | 4317114205418 |
10 | 1230110130113 |
11 | 434761110547 |
12 | 17a4a1488315 |
13 | 8bcca72c447 |
14 | 4377543da5b |
15 | 21ee831a8c8 |
hex | 11e6846ffc1 |
1230110130113 has 8 divisors (see below), whose sum is σ = 1294872463200. Its totient is φ = 1165349766528.
The previous prime is 1230110130031. The next prime is 1230110130127. The reversal of 1230110130113 is 3110310110321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1230110130113 - 216 = 1230110064577 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1230110130091 and 1230110130100.
It is not an unprimeable number, because it can be changed into a prime (1230110130143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 889073 + ... + 1802961.
It is an arithmetic number, because the mean of its divisors is an integer number (161859057900).
Almost surely, 21230110130113 is an apocalyptic number.
It is an amenable number.
1230110130113 is a deficient number, since it is larger than the sum of its proper divisors (64762333087).
1230110130113 is an equidigital number, since it uses as much as digits as its factorization.
1230110130113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 984751.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1230110130113 its reverse (3110310110321), we get a palindrome (4340420240434).
The spelling of 1230110130113 in words is "one trillion, two hundred thirty billion, one hundred ten million, one hundred thirty thousand, one hundred thirteen".
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