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123011113 is a prime number
BaseRepresentation
bin1110101010100…
…00000000101001
322120110121112011
413111100000221
5222442323423
620112315521
73022401661
oct725200051
9276417464
10123011113
1163489085
1235242ba1
131c63c654
14124a11a1
15abecb0d
hex7550029

123011113 has 2 divisors, whose sum is σ = 123011114. Its totient is φ = 123011112.

The previous prime is 123011081. The next prime is 123011117. The reversal of 123011113 is 311110321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90782784 + 32228329 = 9528^2 + 5677^2 .

It is a cyclic number.

It is not a de Polignac number, because 123011113 - 25 = 123011081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123011093 and 123011102.

It is not a weakly prime, because it can be changed into another prime (123011117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505556 + 61505557.

It is an arithmetic number, because the mean of its divisors is an integer number (61505557).

Almost surely, 2123011113 is an apocalyptic number.

It is an amenable number.

123011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

123011113 is an equidigital number, since it uses as much as digits as its factorization.

123011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 123011113 is about 11091.0375078259. The cubic root of 123011113 is about 497.3339603985. Note that the first 3 decimals are identical.

Adding to 123011113 its reverse (311110321), we get a palindrome (434121434).

The spelling of 123011113 in words is "one hundred twenty-three million, eleven thousand, one hundred thirteen".