Base | Representation |
---|---|
bin | 11011111110000011001000… |
… | …000100101010011101100111 |
3 | 121010112202110102111112122021 |
4 | 123332003020010222131213 |
5 | 112110403434311220033 |
6 | 1113342324020244011 |
7 | 34624160464105054 |
oct | 3376031004523547 |
9 | 533482412445567 |
10 | 123011220023143 |
11 | 36216846897391 |
12 | 11968494840607 |
13 | 5383ba662c30a |
14 | 2253abc14c02b |
15 | e34c0ddeab2d |
hex | 6fe0c812a767 |
123011220023143 has 4 divisors (see below), whose sum is σ = 125332186438728. Its totient is φ = 120690253607560.
The previous prime is 123011220023137. The next prime is 123011220023147. The reversal of 123011220023143 is 341320022110321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123011220023143 - 225 = 123011186468711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123011220023147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1160483207713 + ... + 1160483207818.
It is an arithmetic number, because the mean of its divisors is an integer number (31333046609682).
Almost surely, 2123011220023143 is an apocalyptic number.
123011220023143 is a deficient number, since it is larger than the sum of its proper divisors (2320966415585).
123011220023143 is an equidigital number, since it uses as much as digits as its factorization.
123011220023143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2320966415584.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 123011220023143 its reverse (341320022110321), we get a palindrome (464331242133464).
The spelling of 123011220023143 in words is "one hundred twenty-three trillion, eleven billion, two hundred twenty million, twenty-three thousand, one hundred forty-three".
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