Base | Representation |
---|---|
bin | 111001010010000010… |
… | …1111101101100000011 |
3 | 102202111220222201011002 |
4 | 1302210011331230003 |
5 | 4003412100023412 |
6 | 132302212242215 |
7 | 11613232456304 |
oct | 1624405755403 |
9 | 382456881132 |
10 | 123012111107 |
11 | 48195147846 |
12 | 1ba1061036b |
13 | b7a524c332 |
14 | 5d4d3c27ab |
15 | 32ee63cdc2 |
hex | 1ca417db03 |
123012111107 has 2 divisors, whose sum is σ = 123012111108. Its totient is φ = 123012111106.
The previous prime is 123012111091. The next prime is 123012111109. The reversal of 123012111107 is 701111210321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123012111107 - 24 = 123012111091 is a prime.
Together with 123012111109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (123012111109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506055553 + 61506055554.
It is an arithmetic number, because the mean of its divisors is an integer number (61506055554).
Almost surely, 2123012111107 is an apocalyptic number.
123012111107 is a deficient number, since it is larger than the sum of its proper divisors (1).
123012111107 is an equidigital number, since it uses as much as digits as its factorization.
123012111107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 123012111107 its reverse (701111210321), we get a palindrome (824123321428).
The spelling of 123012111107 in words is "one hundred twenty-three billion, twelve million, one hundred eleven thousand, one hundred seven".
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