Base | Representation |
---|---|
bin | 11011111110000100000011… |
… | …110001001100001000001010 |
3 | 121010112212001020001102201211 |
4 | 123332010003301030020022 |
5 | 112110413012204113424 |
6 | 1113343011234403334 |
7 | 34624224345001510 |
oct | 3376040361141012 |
9 | 533485036042654 |
10 | 123012221551114 |
11 | 36217210164155 |
12 | 1196871413054a |
13 | 5384005c82b0c |
14 | 2253b751764b0 |
15 | e34c6bcceb94 |
hex | 6fe103c4c20a |
123012221551114 has 128 divisors (see below), whose sum is σ = 220464564756480. Its totient is φ = 50384681290944.
The previous prime is 123012221551097. The next prime is 123012221551117. The reversal of 123012221551114 is 411155122210321.
It is a happy number.
It is a super-2 number, since 2×1230122215511142 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (123012221551117) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9518853057 + ... + 9518865979.
It is an arithmetic number, because the mean of its divisors is an integer number (1722379412160).
Almost surely, 2123012221551114 is an apocalyptic number.
123012221551114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
123012221551114 is a deficient number, since it is larger than the sum of its proper divisors (97452343205366).
123012221551114 is a wasteful number, since it uses less digits than its factorization.
123012221551114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14264.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 123012221551114 its reverse (411155122210321), we get a palindrome (534167343761435).
The spelling of 123012221551114 in words is "one hundred twenty-three trillion, twelve billion, two hundred twenty-one million, five hundred fifty-one thousand, one hundred fourteen".
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