Base | Representation |
---|---|
bin | 11011111110000100001110… |
… | …011111110110010000000001 |
3 | 121010112212111202202112212102 |
4 | 123332010032133312100001 |
5 | 112110413344244220213 |
6 | 1113343041144440145 |
7 | 34624231662002516 |
oct | 3376041637662001 |
9 | 533485452675772 |
10 | 123012401554433 |
11 | 362172a2829326 |
12 | 11968764479055 |
13 | 5384034358361 |
14 | 2253b9103130d |
15 | e34c7c9d9158 |
hex | 6fe10e7f6401 |
123012401554433 has 8 divisors (see below), whose sum is σ = 131185464207840. Its totient is φ = 114943454349120.
The previous prime is 123012401554429. The next prime is 123012401554457. The reversal of 123012401554433 is 334455104210321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 123012401554433 - 22 = 123012401554429 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123012401554633) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26028859583 + ... + 26028864308.
It is an arithmetic number, because the mean of its divisors is an integer number (16398183025980).
Almost surely, 2123012401554433 is an apocalyptic number.
It is an amenable number.
123012401554433 is a deficient number, since it is larger than the sum of its proper divisors (8173062653407).
123012401554433 is a wasteful number, since it uses less digits than its factorization.
123012401554433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52057724047.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 123012401554433 its reverse (334455104210321), we get a palindrome (457467505764754).
The spelling of 123012401554433 in words is "one hundred twenty-three trillion, twelve billion, four hundred one million, five hundred fifty-four thousand, four hundred thirty-three".
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