Base | Representation |
---|---|
bin | 11011111110000100111110… |
… | …001001101001110001101111 |
3 | 121010112221120111010202101011 |
4 | 123332010332021221301233 |
5 | 112110422013431330133 |
6 | 1113343252344330051 |
7 | 34624260540354610 |
oct | 3376047611516157 |
9 | 533487514122334 |
10 | 123013201042543 |
11 | 3621767304a5a9 |
12 | 11968948173927 |
13 | 5384130b8c246 |
14 | 2253c292a5c07 |
15 | e34cc7cae6cd |
hex | 6fe13e269c6f |
123013201042543 has 4 divisors (see below), whose sum is σ = 140586515477200. Its totient is φ = 105439886607888.
The previous prime is 123013201042517. The next prime is 123013201042549. The reversal of 123013201042543 is 345240102310321.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 123013201042543 - 213 = 123013201034351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123013201042549) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8786657217318 + ... + 8786657217331.
It is an arithmetic number, because the mean of its divisors is an integer number (35146628869300).
Almost surely, 2123013201042543 is an apocalyptic number.
123013201042543 is a deficient number, since it is larger than the sum of its proper divisors (17573314434657).
123013201042543 is an equidigital number, since it uses as much as digits as its factorization.
123013201042543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17573314434656.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 123013201042543 its reverse (345240102310321), we get a palindrome (468253303352864).
The spelling of 123013201042543 in words is "one hundred twenty-three trillion, thirteen billion, two hundred one million, forty-two thousand, five hundred forty-three".
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