Base | Representation |
---|---|
bin | 1011001100000001111111… |
… | …0100001100010001100011 |
3 | 1121112222212011000201200002 |
4 | 2303000133310030101203 |
5 | 3103021100422024303 |
6 | 42055052021450215 |
7 | 2406512115466514 |
oct | 263003764142143 |
9 | 47488764021602 |
10 | 12301320111203 |
11 | 3a12a625651a2 |
12 | 14680b327096b |
13 | 6b3017b78386 |
14 | 30755c198a0b |
15 | 164ebb443788 |
hex | b301fd0c463 |
12301320111203 has 2 divisors, whose sum is σ = 12301320111204. Its totient is φ = 12301320111202.
The previous prime is 12301320111167. The next prime is 12301320111293. The reversal of 12301320111203 is 30211102310321.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12301320111203 - 230 = 12300246369379 is a prime.
It is a super-2 number, since 2×123013201112032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12301320111293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150660055601 + 6150660055602.
It is an arithmetic number, because the mean of its divisors is an integer number (6150660055602).
Almost surely, 212301320111203 is an apocalyptic number.
12301320111203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12301320111203 is an equidigital number, since it uses as much as digits as its factorization.
12301320111203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 12301320111203 its reverse (30211102310321), we get a palindrome (42512422421524).
The spelling of 12301320111203 in words is "twelve trillion, three hundred one billion, three hundred twenty million, one hundred eleven thousand, two hundred three".
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