Base | Representation |
---|---|
bin | 11011111110000100111110… |
… | …010010010010001000101010 |
3 | 121010112221120122101200212221 |
4 | 123332010332102102020222 |
5 | 112110422020021230002 |
6 | 1113343252505024254 |
7 | 34624260565526653 |
oct | 3376047622221052 |
9 | 533487518350787 |
10 | 123013203305002 |
11 | 362176743553aa |
12 | 11968948a8508a |
13 | 53841314a1c8a |
14 | 2253c296d452a |
15 | e34cc80a9c37 |
hex | 6fe13e49222a |
123013203305002 has 4 divisors (see below), whose sum is σ = 184519804957506. Its totient is φ = 61506601652500.
The previous prime is 123013203304987. The next prime is 123013203305009. The reversal of 123013203305002 is 200503302310321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 120873071304441 + 2140132000561 = 10994229^2 + 1462919^2 .
It is not an unprimeable number, because it can be changed into a prime (123013203305009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30753300826249 + ... + 30753300826252.
Almost surely, 2123013203305002 is an apocalyptic number.
123013203305002 is a deficient number, since it is larger than the sum of its proper divisors (61506601652504).
123013203305002 is an equidigital number, since it uses as much as digits as its factorization.
123013203305002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61506601652503.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 123013203305002 its reverse (200503302310321), we get a palindrome (323516505615323).
The spelling of 123013203305002 in words is "one hundred twenty-three trillion, thirteen billion, two hundred three million, three hundred five thousand, two".
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