Base | Representation |
---|---|
bin | 111001010010000101… |
… | …0001110110110000001 |
3 | 102202112000002112220211 |
4 | 1302210022032312001 |
5 | 4003412341324303 |
6 | 132302252234121 |
7 | 11613245126245 |
oct | 1624412166601 |
9 | 382460075824 |
10 | 123013229953 |
11 | 48195841409 |
12 | 1ba10a6b941 |
13 | b7a5551683 |
14 | 5d4d5d4425 |
15 | 32ee7ae66d |
hex | 1ca428ed81 |
123013229953 has 2 divisors, whose sum is σ = 123013229954. Its totient is φ = 123013229952.
The previous prime is 123013229951. The next prime is 123013229981. The reversal of 123013229953 is 359922310321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119002921024 + 4010308929 = 344968^2 + 63327^2 .
It is a cyclic number.
It is not a de Polignac number, because 123013229953 - 21 = 123013229951 is a prime.
Together with 123013229951, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (123013229951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506614976 + 61506614977.
It is an arithmetic number, because the mean of its divisors is an integer number (61506614977).
Almost surely, 2123013229953 is an apocalyptic number.
It is an amenable number.
123013229953 is a deficient number, since it is larger than the sum of its proper divisors (1).
123013229953 is an equidigital number, since it uses as much as digits as its factorization.
123013229953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 87480, while the sum is 40.
The spelling of 123013229953 in words is "one hundred twenty-three billion, thirteen million, two hundred twenty-nine thousand, nine hundred fifty-three".
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