Base | Representation |
---|---|
bin | 11011111110000110110111… |
… | …001001110101110110101111 |
3 | 121010120010210222010010220021 |
4 | 123332012313021311312233 |
5 | 112110440143132311101 |
6 | 1113344230024303011 |
7 | 34624362051022135 |
oct | 3376066711656657 |
9 | 533503728103807 |
10 | 123015231135151 |
11 | 36218514a80193 |
12 | 11969214011a67 |
13 | 5384395641784 |
14 | 2253d7cb55755 |
15 | e34d961185a1 |
hex | 6fe1b7275daf |
123015231135151 has 2 divisors, whose sum is σ = 123015231135152. Its totient is φ = 123015231135150.
The previous prime is 123015231135103. The next prime is 123015231135157. The reversal of 123015231135151 is 151531132510321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123015231135151 - 29 = 123015231134639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123015231135157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61507615567575 + 61507615567576.
It is an arithmetic number, because the mean of its divisors is an integer number (61507615567576).
Almost surely, 2123015231135151 is an apocalyptic number.
123015231135151 is a deficient number, since it is larger than the sum of its proper divisors (1).
123015231135151 is an equidigital number, since it uses as much as digits as its factorization.
123015231135151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 34.
Adding to 123015231135151 its reverse (151531132510321), we get a palindrome (274546363645472).
The spelling of 123015231135151 in words is "one hundred twenty-three trillion, fifteen billion, two hundred thirty-one million, one hundred thirty-five thousand, one hundred fifty-one".
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