123020000041 has 2 divisors, whose sum is σ = 123020000042. Its totient is φ = 123020000040.

The previous prime is 123019999987. The next prime is 123020000053. The reversal of 123020000041 is 140000020321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73959522025 + 49060478016 = 271955^2 + 221496^2 .

It is a cyclic number.

It is not a de Polignac number, because 123020000041 - 2⁷ = 123019999913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123019999976 and 123020000030.

It is not a weakly prime, because it can be changed into another prime (123020006041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61510000020 + 61510000021.

It is an arithmetic number, because the mean of its divisors is an integer number (61510000021).

Almost surely, 2^123020000041 is an apocalyptic number.

It is an amenable number.

123020000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

123020000041 is an equidigital number, since it uses as much as digits as its factorization.

123020000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 123020000041 its reverse (140000020321), we get a palindrome (263020020362).

The spelling of 123020000041 in words is "one hundred twenty-three billion, twenty million, forty-one", and thus it is an aban number.