123023000354035 has 8 divisors (see below), whose sum is σ = 147670854942960. Its totient is φ = 98389563937824.

The previous prime is 123023000354021. The next prime is 123023000354071. The reversal of 123023000354035 is 530453000320321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 123023000354035 - 2⁵ = 123023000354003 is a prime.

It is a super-3 number, since 3×123023000354035³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 123023000353988 and 123023000354006.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3604524405 + ... + 3604558534.

It is an arithmetic number, because the mean of its divisors is an integer number (18458856867870).

Almost surely, 2^{123023000354035} is an apocalyptic number.

123023000354035 is a deficient number, since it is larger than the sum of its proper divisors (24647854588925).

123023000354035 is an equidigital number, since it uses as much as digits as its factorization.

123023000354035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7209086357.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 123023000354035 its reverse (530453000320321), we get a palindrome (653476000674356).

The spelling of 123023000354035 in words is "one hundred twenty-three trillion, twenty-three billion, three hundred fifty-four thousand, thirty-five".