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12302391433 is a prime number
BaseRepresentation
bin10110111010100011…
…11001100010001001
31011202101010020102011
423131101321202021
5200143403011213
65352430535521
7613602413263
oct133521714211
934671106364
1012302391433
115243419852
1224740675a1
1312109bbc77
14849c54b33
154c00a303d
hex2dd479889

12302391433 has 2 divisors, whose sum is σ = 12302391434. Its totient is φ = 12302391432.

The previous prime is 12302391427. The next prime is 12302391443. The reversal of 12302391433 is 33419320321.

12302391433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7117959424 + 5184432009 = 84368^2 + 72003^2 .

It is a cyclic number.

It is not a de Polignac number, because 12302391433 - 225 = 12268837001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12302391395 and 12302391404.

It is not a weakly prime, because it can be changed into another prime (12302391443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151195716 + 6151195717.

It is an arithmetic number, because the mean of its divisors is an integer number (6151195717).

Almost surely, 212302391433 is an apocalyptic number.

It is an amenable number.

12302391433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12302391433 is an equidigital number, since it uses as much as digits as its factorization.

12302391433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 31.

The spelling of 12302391433 in words is "twelve billion, three hundred two million, three hundred ninety-one thousand, four hundred thirty-three".