Base | Representation |
---|---|
bin | 11011111110010100111111… |
… | …010011010010100001101001 |
3 | 121010121120222010102020201211 |
4 | 123332110333103102201221 |
5 | 112111212224423341040 |
6 | 1113355215142313121 |
7 | 34625440003046143 |
oct | 3376247723224151 |
9 | 533546863366654 |
10 | 123030400215145 |
11 | 36223999586535 |
12 | 119701481287a1 |
13 | 538594220a157 |
14 | 22549bb5cdc93 |
15 | e35482bca8ea |
hex | 6fe53f4d2869 |
123030400215145 has 4 divisors (see below), whose sum is σ = 147636480258180. Its totient is φ = 98424320172112.
The previous prime is 123030400215113. The next prime is 123030400215167. The reversal of 123030400215145 is 541512004030321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 81889323729984 + 41141076485161 = 9049272^2 + 6414131^2 .
It is a cyclic number.
It is not a de Polignac number, because 123030400215145 - 25 = 123030400215113 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12303040021510 + ... + 12303040021519.
It is an arithmetic number, because the mean of its divisors is an integer number (36909120064545).
Almost surely, 2123030400215145 is an apocalyptic number.
It is an amenable number.
123030400215145 is a deficient number, since it is larger than the sum of its proper divisors (24606080043035).
123030400215145 is an equidigital number, since it uses as much as digits as its factorization.
123030400215145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24606080043034.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 123030400215145 its reverse (541512004030321), we get a palindrome (664542404245466).
The spelling of 123030400215145 in words is "one hundred twenty-three trillion, thirty billion, four hundred million, two hundred fifteen thousand, one hundred forty-five".
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